Integral 2.4 with \(n=1\) can be partitioned over the domain of f,
$$\begin&\mathbb [}] = \int _\mathbb [(x')}] \ f(x') \ \text x'\nonumber \\&= 2 \int _0^m \big [ 1 \big ] \ \Big [ \frac} e^(\frac)^2} \Big ] \ \text x'\nonumber \\&\quad + 2\int _m^ \Big [ \frac (2r + m - |x'|)^2 (x'^2 \nonumber \\&\quad - 3 m^2 + 2|x'|(m+2r)) \Big ] \ \Big [ \frac} e^(\frac)^2} \Big ] \ \text x'\end$$
(A.1)
$$\begin&\mathbb [}] = 2 \Bigg [ \frac \,}}\Big ( \frac}\Big ) \Bigg ] \nonumber \\&\quad +2 \Biggr [ \bigg [ \frac} \bigg ] \bigg [ e^} \sigma ^2 \bigg ( 5 m^2 + 8 m r + 8 r^2 \nonumber \\&\quad - 2 \sigma ^2 - e^} \Big ( 5 m^2 + 12 m r + 12 r^2 - 2 \sigma ^2 \Big ) \bigg ) \nonumber \\&\quad + \frac \bigg (m + 2 r \bigg ) \bigg ( -8 \sigma \sqrt \Big ( m^2 + m r + r^2 \Big ) \,}}\Big (\frac} \Big ) \nonumber \\&\quad + 8 \sigma \sqrt \Big ( m^2 + m r + r^2 \Big ) \,}}\Big ( \frac} \Big ) +3 m^2 \big (\text \Big ( \frac \Big ) \nonumber \\&\quad - \text \Big ( \frac \Big ) \big ) \Big (m + 2 r \Big )^2 \bigg ) \biggr ] \Biggr ] \ , \end$$
(A.2)
where \(\,}}(\cdot )\) is the error function
$$\begin \,}}(x) = \frac} \int _0^x e^ \text t \ , \end$$
(A.3)
and \(\text (\cdot )\) is the exponential integral
$$\begin \text (x) = \int _^x \frac \text t \ . \end$$
(A.4)
For comparison with the \(V_\) numerical results in Fig. 9, we are interested in the limit \(m \rightarrow 0\),
$$\begin&\lim _ \Big [ \mathbb [}] \Big ] = \frac}} \bigg (r^2 \sigma \Big (4 - 6 e^}\Big ) + \sigma ^3\Big (e^} - 1\Big )\bigg ) \nonumber \\&\quad + \,}}\Big (\frac}\Big ) \ . \end$$
(A.5)
Similarly, the integral 2.4 with \(n=2\) can be separated
$$\begin \mathbb [^2}]&= \int _\mathbb [(x')}]^2 \ f(x') \ \text x' \nonumber \\&= 2 \int _0^m \big [ 1 \big ]^2 \ \Big [ \frac} e^(\frac)^2} \Big ] \ \text x'\nonumber \\&+ 2\int _m^ \Big [ \frac (2r + m - |x'|)^2 (x'^2 \nonumber \\ &\quad - 3 m^2 + 2|x'|(m+2r)) \Big ]^2 \ \Big [ \frac} e^(\frac)^2} \Big ] \ \text x' \ , \end$$
(A.6)
which evaluates to
$$\begin&\mathbb [^2}] = 2 \Bigg [ \frac \nonumber \\&\quad erf \Big ( \frac}\Big ) \Bigg ] \nonumber \\&\quad +2 \Bigg [ \bigg [ \frac r^6 \sigma }\bigg ] \bigg [ e^} \Big [ m + 2 r \Big ] \Big [ -9 m^4 (m + 2 r)^2 \nonumber \\&\quad + (61 m^4 + 152 m^3 r + 216 m^2 r^2 + 128 m r^3 \nonumber \\&\quad + 64 r^4) \sigma ^2 + (-m^2 + 20 m r + 20 r^2) \sigma ^4 - 15 \sigma ^6 \Big ] \nonumber \\&\quad + e^} \Big [ 9 m^3 (m + 2 r)^4 - (61 m^5 + 336 m^4 r \nonumber \\&\quad + 768 m^3 r^2 + 1024 m^2 r^3 + 816 m r^4 + 384 r^5) \sigma ^2 \nonumber \\&\qquad + (m^3 + 24 m^2 r + 24 m r^2 + 64 r^3) \sigma ^4 + 15 m \sigma ^6 \Big ] \nonumber \\&\quad + \frac} \,}}\Big ( \frac \sigma )} \Big ) \Big [9 m^4 (m + 2 r)^4 \nonumber \\&\quad - 4 (m + 2 r)^2 (5 m^2 + 2 m r + 2 r^2) (5 m^2 + 8 m r + 8 r^2) \sigma ^2 \nonumber \\&\qquad - 6 (5 m^4 + 20 m^3 r + 44 m^2 r^2 + 48 m r^3 + 24 r^4) \sigma ^4 \nonumber \\&\quad + 36 (m^2 + 2 m r + 2 r^2) \sigma ^6 - 15 \sigma ^8 \Big ] \nonumber \\&\quad + \,}}\Big ( \frac \sigma } \Big ) \Big [ -9 m^4 (m + 2 r)^4 + 4 (m \nonumber \\ &\quad + 2 r)^2 (5 m^2 + 2 m r + 2 r^2) (5 m^2 + 8 m r \nonumber \\&\quad +8 r^2) \sigma ^2 \nonumber \\&\quad + 6 (5 m^4 + 20 m^3 r + 44 m^2 r^2 + 48 m r^3 + 24 r^4) \sigma ^4 \nonumber \\&\quad -36 (m^2 + 2 m r + 2 r^2) \sigma ^6 + 15 \sigma ^8 \Big ] \nonumber \\&\quad + 48 m^2 \sigma \big ( \text \Big ( \frac \Big ) \nonumber \\&\quad - \text \Big ( \frac \Big ) \big ) (m + 2 r)^3 (m^2 + m r + r^2) \bigg ] \Bigg ] \ . \end$$
(A.7)
The variance of \(V_\) is then \(\hbox (V_) = \mathbb [^2}] - \mathbb [}]^2\), or, in the limit \(m \rightarrow 0\),
$$\begin&\lim _ \Big [ \hbox (V_) \Big ] = \frac \bigg [\nonumber \\&\quad -8 \sigma \big (-6 r^2 + \sigma ^2\big ) \big (-8 \sqrt r^3 - 6 r^2 s + \sigma ^3\big ) - 8 e^} \big (\sigma ^3 \nonumber \\&\quad - 4 r^2 \sigma \big )^2 \nonumber \\&\quad + 2\sigma e^} \big (64 r^5 \sqrt + 192 r^4 \sigma + 20 r^3 \sigma ^2 \sqrt \nonumber \\ &\quad - 80 r^2 \sigma ^3 - 15 r \sigma ^4 \sqrt + 8 \sigma ^5\big ) \nonumber \\&\quad + 64 r^3 \sigma e^} \sqrt \big (\sigma ^2 - 4 r^2\big ) \,}}\Big (\frac}\Big ) \nonumber \\ &\quad + \big (64 r^3 \sigma \sqrt (6 r^2 - \sigma ^2) \nonumber \\ &\quad + \pi (256 r^6 + 144 r^4 \sigma ^2 - 72 r^2 \sigma ^4 + 15 \sigma ^6)\big ) \,}}\Big (\frac}\Big ) \nonumber \\ &\quad - 256 \pi r^6 \,}}\Big (\frac}\Big )^2\bigg ] \ . \end$$
(A.8)
Lastly, the integral 2.5
$$\begin p(V_ > V^*)&= p(|x| < x^*) \nonumber \\&= 2 \int _^ f(x') \ \text x' \ , \end$$
(A.9)
requires finding a critical \(x^*\) for which if \(|x| > x^*\), \(V_ < V^*\). The expression
$$\begin x^*\Bigg [ \frac \big (2r + m - x^*\big )^2 \big (^2 - 3 m^2 + 2x^*(m+2r)\big ) - V^* = 0 \Bigg ] \end$$
(A.10)
is quartic in \(x^*\) and has a root within the interval \((m, 2r + m)\) at
$$\begin x^* = \frac (\alpha - \beta ) \ , \end$$
(A.11)
withs
$$\begin \alpha&= \Bigg [\bigg [ 4 (m^2+2 m r+2 r^2) \bigg ] \nonumber \\&\quad + \frac}}\Big [-432 \Big (m^2+2 m r+2 r^2\Big )^3 \nonumber \\&\quad -1296 \Big (m^4+4 m^3 r\nonumber \\ &\quad +4 m^2 r^2\Big ) \Big (m^2+2 m r+2 r^2\Big ) \nonumber \\&\quad +1728 \Big (m^3+3 m^2 r+3 m r^2-2 r^3 V+2 r^3\Big )^2 \nonumber \\ &\quad +\Big (\big (-432 (m^2+2 m r+2 r^2)^3+1728 (m^3 \nonumber \\ &\quad +3 m^2 r+3 m r^2-2 r^3 V+2 r^3)^2 \nonumber \\&\quad -1296 (m^4+4 m^3 r+4 m^2 r^2) (m^2+2 m r+2 r^2)\big )^2 \nonumber \\ &\quad -4 \big (144 m^2 r^2+288 m r^3 +144 r^4\big )^3\Big )^\bigg ]^ \nonumber \\&\quad + \bigg [ 48 \root 3 \of \Big (m^2 r^2+2 m r^3+r^4\Big )\bigg ]\bigg [-432 \Big (m^2+2 m r+2 r^2\Big )^3 \nonumber \\ &\quad +1728 \Big (m^3+3 m^2 r+3 m r^2-2 r^3 V+2 r^3\Big )^2 \nonumber \\&\quad - 1296 \Big (m^4+4 m^3 r+4 m^2 r^2\Big )\nonumber \\&\quad \Big (m^2+2 m r+2 r^2\Big )\nonumber \\ &\quad + \Big (\big (-432 (m^2+2 m r+2 r^2)^3+1728 (m^3+3 m^2 r \nonumber \\ &\quad +3 m r^2-2 r^3 V+2 r^3)^2 \nonumber \\&\quad -1296 (m^4+4 m^3 r+4 m^2 r^2) (m^2+2 m r+2 r^2)\big )^2\nonumber \\ &\quad -4 \big (144 m^2 r^2+288 m r^3+144 r^4\big )^3\Big )^\bigg ]^\Bigg ]^ \ , \end$$
(A.12)
and
$$\begin \beta&= \Bigg [ \bigg [ 8 (m^2+2 r m+2 r^2) \bigg ]\nonumber \\&\quad - \frac}\bigg [\bigg (-432 \Big (m^2+2 r m+2 r^2\Big )^3 \nonumber \\ &\quad -1296 \Big (m^4 +4 r m^3 + 4 r^2 m^2\Big ) \Big (m^2 +2 r m+2 r^2\Big )\nonumber \\ &\quad +1728 \Big (m^3+3 r m^2+3 r^2 m+2 r^3-2 r^3 V\Big )^2\nonumber \\&\quad +\Big (\big (-432(m^2+2 r m+2 r^2)^3-1296 (m^4+4 r m^3 \nonumber \\ &\quad +4 r^2 m^2) (m^2+2 r m+2 r^2)+1728 (m^3+3 r m^2\nonumber \\ &\quad +3 r^2 m+2 r^3-2 r^3 V)^2\big )^2 \nonumber \\&\quad -4 \big (144 r^4+288 m r^3+144 m^2 r^2\big )^3\Big )^\bigg )^\bigg ] \nonumber \\&\quad -\bigg [48\ 2^} (r^4+2 m r^3+m^2 r^2)\bigg ]\bigg [-432 (m^2+2 r m+2 r^2)^3 \nonumber \\ &\quad -1296 (m^4 +4 r m^3+4 r^2 m^2) (m^2+2 r m+2 r^2) \nonumber \\&\quad +1728 (m^3+3 r m^2+3 r^2 m+2 r^3-2 r^3V)^2\nonumber \\&\quad +((-432 (m^2+2 r m+2 r^2)^3-1296 (m^4+4 r m^3 \nonumber \\ &\quad +4 r^2 m^2) (m^2+2 r m+2 r^2) +1728 (m^3+3 r m^2+3 r^2 m\nonumber \\ &\quad +2 r^3-2 r^3 V)^2)^2-4 (144 r^4+288 m r^3+144 m^2 r^2)^3)^\bigg ]^ \nonumber \\&\quad -\bigg [16 (m^3+3 r m^2+3 r^2 m+2 r^3-2 r^3 V)\bigg ]\bigg [4 (m^2+2 r m\nonumber \\&\quad +2r^2)\nonumber \\ &\quad +\frac}\Big [-432 (m^2+2 r m+2 r^2)^3 \nonumber \\&\quad -1296 (m^4+4 r m^3+4 r^2 m^2) (m^2+2 r m+2 r^2)+1728 (m^3\nonumber \\ &\quad +3 r m^2+3 r^2 m+2 r^3-2 r^3 V)^2+((-432 (m^2+2 r m+2 r^2)^3 \nonumber \\&\quad -1296 (m^4+4 r m^3+4 r^2 m^2) (m^2+2 r m+2 r^2)+1728 (m^3\nonumber \\ &\quad +3 r m^2+3 r^2 m\nonumber \\&\quad +2 r^3-2 r^3 V)^2)^2-4 (144 r^4+288 m r^3+144 m^2 r^2)^3)^\Big ]^ \nonumber \\&\quad + \Big [48 \root 3 \of (r^4+2 m r^3+m^2 r^2)\Big ]\Big [-432 (m^2+2 r m+2 r^2)^3\nonumber \\&\quad -1296 (m^4+4 r m^3+4 r^2 m^2) (m^2+2 r m+2 r^2) \nonumber \\&\quad +1728 (m^3+3 r m^2+3 r^2 m+2 r^3-2 r^3V)^2\nonumber \\&+((-432 (m^2+2 r m+2 r^2)^3\nonumber \\&\quad -1296 (m^4+4 r m^3+4 r^2 m^2) (m^2+2 r m+2 r^2)\nonumber \\&\quad +1728 (m^3+3 r m^2+3 r^2 m+2 r^3-2 r^3 V)^2)^2\nonumber \\&-4 (144 r^4+288 m r^3+144 m^2 r^2)^3)^\Big ]^\bigg ]^\Bigg ]^ \end$$
(A.13)
Having found \(x^*\), the equation 2.5 integral is trivial,
$$\begin p(V_ > V^*)&= 2 \int _^ f(x') \ \text x' \nonumber \\&= \,}}\Big (\frac} \Big ) \ . \end$$
(A.14)
Fig. 1
The alternative text for this image may have been generated using AI.\(V_\) is expressed as the intersection volume of spheres having radii r and \(r + m\). The misalignment distance between sphere centers is denoted x
Fig. 2
The alternative text for this image may have been generated using AI.Visualization of \(V_(x)\) (equation 2.3) for example target radii r and margins m. Notice a more rapid coverage fall-off for smaller targets utilizing similar margins
Fig. 3
The alternative text for this image may have been generated using AI.The expected value of \(V_\) for geometric errors x with probability density \(\mathcal (0, \sigma ^2)\) according to equation A.2. The variance of \(V_\) is shown by the boundaries of the shaded region
Fig. 4
The alternative text for this image may have been generated using AI.Probability of meeting coverage objectives \(V_ > 50\%\) and \(V_ > 90\%\), and \(V_ > 95\%\) for various r and m as a function of \(\sigma _x\) according to equation A.14
Fig. 5
The alternative text for this image may have been generated using AI.Clinical single-isocenter multi-target treatment plans were created using an in-house planning script with four arcs and systematically generated optimization structures
Fig. 6
The alternative text for this image may have been generated using AI.Relative DVH perturbations for 8 targets for 1.2 mm translation uncertainties in the x, y, and z directions. Nominal DVHs are shown with solid lines and six perturbed DVHs are shown with dashed lines in each subplot
Fig. 7
The alternative text for this image may have been generated using AI.Sensitivity of \(V_\) to translation errors, stratified by shift direction (left) and number of targets (right). First and third quartiles are represented by the bottoms and tops of the error bars. Translations of 1 mm can reduce \(V_\) by as much as 10%
Fig. 8
The alternative text for this image may have been generated using AI.Measured \(V_\) compared to samples from the SVM ensemble. Error bar caps and the shaded region’s boundaries are representative of the first and third quartiles of the coverage distribution for a given shift. Notice an increased variance in the ensemble’s description of coverage for larger |x|
Fig. 9
The alternative text for this image may have been generated using AI.The SVM ensembles are used to describe coverage distributions for various \(\sigma _\). Left: The center line shows the \(V_\) median and the shaded region shows the first and third quartiles. Right: The center line shows the expected value \(\mathbb [V_]\) and the shaded region shows \(\pm \sigma _}\)
Fig. 10
The alternative text for this image may have been generated using AI.The probability of achieving \(V_ > 95\%\) is evaluated for error models \(\sigma _ \in (0 \hbox , 3 \hbox )\). For the analytical model we used parameters \((r = 7.9\) mm, \(m= 0\) mm) for \(p(V_ > V^*)\) and \((r = 7.9\) mm, \(m= 0.4\) mm) for \(p(V_ > V^*)\)
Table 1 Notation used throughout the manuscriptTable 2 Tabulated tolerances on maximum translational uncertainty required to achieve coverage with at least some probability
Comments (0)